The magnetic flux linked with a closed circuit of resistance `8Omega` varies with time according to the expression `phi = (5t^2 – 4t + 2)` where `phi` is in milliweber and t in second. Calculate the value of induce current at `t = 15 `s.

Explanation

To solve the problem, we need to calculate the induced current in a closed circuit given the magnetic flux as a function of time and the resistance of the circuit. Here are the steps to find the solution:

### Step 1: Write down the expression for magnetic flux
The magnetic flux linked with the circuit is given by:
\[ \phi(t) = 5t^2 - 4t + 2 \quad \text{(in milliweber)} \]

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