Show that maximum intensity in interference pattern is four times the intensity due to each slit. Hence show that interference involves only redistribution of energy.

Assertion (A) : The maximum intensity in interference pattern is four times the intensity in interference pattern is four times the intensity due to each slit of equal width. Reason (R ) : Intensity is directly proportinal to square of amplitude.

Assertion (A) : In interfrence pattern intensity of successive fringes due to achromatic light is not same Reason (R ) : In interferance, only redistribution of energy takes place

Two waves of intensity I undergo interference. The maximum intensity obtained is

The ratio of intensity at maxima and minima in the interference pattern is 25:9. What will be the widths of the two slits in Young's interference experiment ?

The ratio of the intensities of the maxima and minima in an interference pattern is 49: 9. What is the ratio of the intensities of the two coherent sources employed in the interference experiment?

(a) The ratio of the widths of two slits in Young's double-slit experiment is 4 : 1. Evaluate the ratio of intensities at maxima and minima in the interference pattern. (b) Does the appearance of bright and dark fringes in the interference pattern violate, in any way, conservation of energy ? Explain.

The intensity ratio in the interference pattern is 1 : 9 . What is the amplitude ratio and the ratio of widths of two slits ?

Find the maxinum intensity in case of interference of n identical waves each of intensity I_(0) if the interference is (a) coherent and (b) incoherent.