An EM wave travelling through a medium has electric field vector. `E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C`. Here x is in m and t in s. Then find :
Direction of propagation

An EM wave travelling through a medium has electric field vector. E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C . Here x is in m and t in s. Then find : Frequency

An EM wave travelling through a medium has electric field vector. E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C . Here x is in m and t in s. Then find : Wavelength

An EM wave travelling through a medium has electric field vector. E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C . Here x is in m and t in s. Then find : Speed of wave

An EM wave travelling through a medium has electric field vector. E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C . Here x is in m and t in s. Then find : Refractive index of medium

An EM wave travelling through a medium has electric field vector. E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C . Here x is in m and t in s. Then find : Amplitude of magnetic field vector.

An EM wave is travelling in vacuum. Amplitude of the electric field vector is 5 × 10^4 V//m . Calculate amplitude of magnetic field vector

Suppose that the electric field of an electromagnetic wave in vacuum is E={(3.0 N //C) cos [1.8 rad//m) y +(5.4 xx 10^6 rad // s)t]}hat i (a) What is the direction of propagation of wave? (b) What is the wavelength lambda ? (c) What is the frequency f ? (d) What is the amplitude of the magnetic field of the wave (e) write an expression for the magnetic field of the wave.

Suppose that the electric field part of an electromagnetic wave in vacuum is vecE = ((3.1 N//C cos [(1.8 rad // m ) y + ( 5.4 xx 10 ^6 rad s^(-1) t ) ]} hati (a) What is the direction of propagation ? (b ) what is the wavelength lamda ? (c ) what is the frequency v? (d) what is the amplitude of the magnetic field part of the wave ? (e ) write an expression for the maganetic field part of the wave .