An EM wave travelling through a medium has electric field vector. `E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C`. Here x is in m and t in s. Then find :
Amplitude of magnetic field vector.

An EM wave travelling through a medium has electric field vector. E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C . Here x is in m and t in s. Then find : Wavelength

An EM wave travelling through a medium has electric field vector. E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C . Here x is in m and t in s. Then find : Frequency

An EM wave travelling through a medium has electric field vector. E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C . Here x is in m and t in s. Then find : Speed of wave

An EM wave travelling through a medium has electric field vector. E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C . Here x is in m and t in s. Then find : Refractive index of medium

An EM wave travelling through a medium has electric field vector. E_y = 4 times 10^5 cos (3.14 × 10^8 t – 1.57 x) N//C . Here x is in m and t in s. Then find : Direction of propagation

An EM wave is travelling in vacuum. Amplitude of the electric field vector is 5 × 10^4 V//m . Calculate amplitude of magnetic field vector

The electric field part of an electromagnetic wave in vacuum is given by E = 6 cos [1.2 ("rad")/(m) y + 3.6 xx 10^(8) ("red")/(s) t ] hat(i) (N)/(C ) , then find i) frequency of propagation (f) (ii) Ampitude of magnetic field in electromagnetic wave