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A beam of light consisting of two wavelength `800 nm and 600 nm` is used to obtain the interference fringes in YDSE on a screen held `1.4 m` away. If the two slits are separated by `0.28 mm`, calculate the least distance from thecentral bright maximum, where the bright fringes of the two waveength coincide.

Text Solution

Verified by Experts

`x=n lamda_1D/d=(n+1)lamda_2 D/d`
`n times 800=(n+1) lamda_2 D/d`
`n=3`
`x=nlamda_1 D/d=3 times 800 times (10^-9 times 1.4)/(0.28 times 10^-3)=12 mm`
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