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Let Z is be the set of integers , if A={...

Let Z is be the set of integers , if `A={"x"inZ:|x-3|^((x^2-5x+6))=1} and B{x in Z : 10 lt3x+1lt 22}`, then the number of subsets of the set `AxxB` is

A

`2^6`

B

`2^8`

C

`2^15`

D

`2^9`

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The correct Answer is:
To solve the problem, we need to find the sets A and B based on the given conditions and then determine the number of subsets of the Cartesian product A × B. ### Step 1: Determine the set A We are given the condition for set A as: \[ A = \{ x \in \mathbb{Z} : |x - 3|^{(x^2 - 5x + 6)} = 1 \} \] The expression \( |x - 3|^{(x^2 - 5x + 6)} = 1 \) can be true under two conditions: 1. \( |x - 3| = 1 \) 2. \( x^2 - 5x + 6 = 0 \) #### Case 1: \( |x - 3| = 1 \) This gives us two equations: 1. \( x - 3 = 1 \) → \( x = 4 \) 2. \( x - 3 = -1 \) → \( x = 2 \) So from this case, we get \( x = 2 \) and \( x = 4 \). #### Case 2: \( x^2 - 5x + 6 = 0 \) Factoring the quadratic: \[ (x - 2)(x - 3) = 0 \] This gives us: 1. \( x = 2 \) 2. \( x = 3 \) However, we need to ensure that \( |x - 3|^{(x^2 - 5x + 6)} \) does not equal 0. If \( x = 3 \), the exponent becomes 0, which makes the expression equal to 1, but we want to exclude this case since \( |x - 3| \) would be 0. Thus, from this case, we only take \( x = 2 \). ### Conclusion for set A: Combining both cases, we have: \[ A = \{ 2, 4 \} \] ### Step 2: Determine the set B We are given the condition for set B as: \[ B = \{ x \in \mathbb{Z} : 10 < 3x + 1 < 22 \} \] We can break this down into two inequalities: 1. \( 3x + 1 > 10 \) 2. \( 3x + 1 < 22 \) #### Solving the inequalities: 1. From \( 3x + 1 > 10 \): \[ 3x > 9 \] \[ x > 3 \] 2. From \( 3x + 1 < 22 \): \[ 3x < 21 \] \[ x < 7 \] Combining these results, we have: \[ 3 < x < 7 \] The integer solutions for \( x \) are: \[ x = 4, 5, 6 \] ### Conclusion for set B: Thus, we have: \[ B = \{ 4, 5, 6 \} \] ### Step 3: Find the Cartesian product A × B Now we need to find the Cartesian product \( A \times B \): - Set A has 2 elements: \( |A| = 2 \) - Set B has 3 elements: \( |B| = 3 \) The number of elements in the Cartesian product \( A \times B \) is: \[ |A \times B| = |A| \times |B| = 2 \times 3 = 6 \] ### Step 4: Calculate the number of subsets of A × B The number of subsets of a set with \( n \) elements is given by \( 2^n \). Therefore, the number of subsets of \( A \times B \) is: \[ \text{Number of subsets} = 2^{|A \times B|} = 2^6 = 64 \] ### Final Answer: The number of subsets of the set \( A \times B \) is \( 64 \). ---
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