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If f(x)=(x^(3)+x+1)tan(pi[x]) (where, [x...

If `f(x)=(x^(3)+x+1)tan(pi[x])` (where, `[x]` represents the greatest integer part of x), then

A

domain of f(x) is `R-(2n+1)(pi)/(2),n in I`

B

range of `f(x) in R`

C

`f(x)` is an even function

D

`f(x)` is a non - periodic function

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The correct Answer is:
To solve the problem, we need to analyze the function \( f(x) = (x^3 + x + 1) \tan(\pi [x]) \), where \([x]\) denotes the greatest integer part of \(x\). ### Step 1: Understand the function components The function consists of two parts: 1. \( g(x) = x^3 + x + 1 \) - a polynomial function. 2. \( h(x) = \tan(\pi [x]) \) - a trigonometric function based on the greatest integer function. ### Step 2: Analyze the greatest integer function The greatest integer function \([x]\) takes any real number \(x\) and gives the largest integer less than or equal to \(x\). For example: - If \( x = 2.3 \), then \([x] = 2\). - If \( x = 3.7 \), then \([x] = 3\). ### Step 3: Analyze the behavior of \(\tan(\pi [x])\) The tangent function \(\tan(\pi n)\) (where \(n\) is an integer) is equal to 0 for all integer values. Thus, for any \(x\) such that \([x] = n\), we have: \[ \tan(\pi [x]) = \tan(\pi n) = 0 \] This means that the function \(h(x)\) will always be 0 for any value of \(x\). ### Step 4: Determine \(f(x)\) Since \(\tan(\pi [x]) = 0\) for all \(x\), we can substitute this into the function: \[ f(x) = (x^3 + x + 1) \cdot 0 = 0 \] Thus, \(f(x) = 0\) for all \(x\). ### Step 5: Determine the domain and range - **Domain**: Since \(f(x)\) is defined for all real numbers, the domain is \(\mathbb{R}\). - **Range**: The function is constantly 0, so the range is \{0\}. ### Step 6: Determine if the function is even or odd A function \(f(x)\) is even if \(f(-x) = f(x)\) for all \(x\). Since \(f(x) = 0\) for all \(x\), we have: \[ f(-x) = 0 = f(x) \] Thus, the function is even. ### Step 7: Determine if the function is periodic A function is periodic if there exists a positive number \(T\) such that \(f(x + T) = f(x)\) for all \(x\). Since \(f(x) = 0\) for all \(x\), it is trivially periodic with any \(T > 0\). ### Summary of Results - **Domain**: \(\mathbb{R}\) - **Range**: \{0\} - **Even or Odd**: Even - **Periodic or Non-Periodic**: Periodic
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