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A five digit number is chosen at random....

A five digit number is chosen at random. The probability that all the digits are distinct and digits at odd places are odd and digits at even places are even, is

A

`.^(5)P_(2)xx(.^(5)P_(3))/(9xx10^(4))`

B

`(.^(5)P_(2)xx.^(5)P_(3))/(10^(5))`

C

`(.^(5)C_(2)xx.^(5)C_(3)xx2)/(10^(4)xx9)`

D

`(.^(5)C_(2)xx.^(5)C_(3))/(9xx10^(4))`

Text Solution

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The correct Answer is:
A
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