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Lying in the plane x+y+z=6 is a line L p...

Lying in the plane `x+y+z=6` is a line L passing through (1, 2, 3) and perpendicular to the line of intersection of planes `x+y+z=6` and `2x-y+z=4`, then the equation of L is

A

`(x-1)/(4)=(y-2)/(-7)=(z-3)/(3)`

B

`(x-1)/(2)(y-2)/(1)=(z-3)/(-3)`

C

`(x-1)/(4)=(y-2)/(-5)=(z-3)/(1)`

D

`(x-1)/(3)=(y-2)/(1)=(z-3)/(-4)`

Text Solution

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The correct Answer is:
C
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