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The solubility product of AgCl is 1.8xx1...

The solubility product of AgCl is `1.8xx10^(-10)`. Precipitation of AgCl will occur only when equal volumes of solutions of :

A

`10^(-4)" M Ag"^(+) and 10^(-4)"M Cl"^(-)`

B

`10^(-7)"M Ag"^(+) and 10^(-7)"M Cl"^(-)`

C

`10^(-5)"M Ag"^(+) and 10^(-5)"M Cl"^(-)`

D

`10^(-10)"M Ag"^(+) and 10^(-10)"M Cl"^(-)`

Text Solution

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The correct Answer is:
A
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