Which of the following statements is incorrect for ethylene dichloride and ethylidene chloride?

Options

A. These are structural isomers
B. Both of these yields same product on reaction with alcoholic KOH solution
C. Both of these yeilds same product on treatement with aqueous KOH solution
D. Both of these yeilds same product on reduction

Answer

To determine which statement is incorrect for ethylene dichloride (1,2-dichloroethane) and ethylidene chloride (1-chloro-2-methylpropene), we need to analyze the properties and reactions of both compounds.

### Step-by-Step Solution:

1. **Identify the Chemical Structures:**
- **Ethylene Dichloride (1,2-dichloroethane)**: The structure is CH2Cl-CH2Cl.
- **Ethylidene Chloride (1-chloro-2-methylpropene)**: The structure is CH3-CHCl-CH2.

2. **Check for Structural Isomerism:**
- Both compounds have the same molecular formula (C2H4Cl2), but their structures differ in the connectivity of atoms. This confirms that they are structural isomers.

3. **Evaluate the Reaction with Alcoholic KOH:**
- Both compounds can undergo elimination reactions when treated with alcoholic KOH, leading to the formation of alkenes. This reaction is valid for both compounds, producing different alkenes.

4. **Consider Reduction Reactions:**
- In reduction reactions, chlorine atoms can be replaced by hydrogen atoms. Both compounds can be reduced to form ethane (C2H6), confirming that this statement is correct.

5. **Analyze the Reaction with Aqueous KOH:**
- When treated with aqueous KOH, the reaction mechanism involves nucleophilic substitution (SN2).
- For ethylene dichloride, the reaction would yield two molecules of ethanol (CH2OH-CH2OH).
- For ethylidene chloride, the reaction would yield different products due to the presence of a methyl group, resulting in different alcohols.

6. **Conclusion:**
- The statement that both compounds yield the same product when treated with aqueous KOH is incorrect because the products differ due to the structural differences in the two compounds.

### Final Answer:
The incorrect statement is that both compounds yield the same product when treated with aqueous KOH.