A screw gauge with a pitch of `0.5mm` and a circular scale with `50` divisions is used to measure the thicknes of a thin sheet of Aluminium. Before starting the measurement, it is found that wen the jaws of the screw gauge are brought in cintact, the `45^(th)` division coincide with the main scale line and the zero of the main scale is barely visible. what is the thickness of the sheet if the main scale readind is `0.5 mm` and the `25th` division coincide with the main scale line?

Options

A. `Deltaf=f[(c(c-v))/(v(c+v))]`
B. `Deltaf=f[(v(c-v))/(c(c+v))]`
C. `Deltaf=f[(c(c+v))/(v(c-v))]`
D. `Delta f = f [(v(c+v))/(c(c-v))]`

Answer

D