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The figure shows an RC circuit with a pa...

The figure shows an RC circuit with a parallel plate capacitor. Before switching on the circuit, plate A of the capacitor has a charge. `-Q_(0)` while plate B has no net charge. If at `t = 0`, the switch is closed then after how much time (in seconds) will the net charge on plate A becomes zero? [Given : `C = 1 mu F, Q_(0) = 1 mC, epsilon = 1000 V and R = (2 xx 10^(6))/(1n 3) Omega]`

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Knowledge Check

  • In Figure the plate A has 100 muC charge, while the plate B has 60 mu C charge. . When only switch S_(1) is closed , then

    A
    `q_(1) = 10 mu C`
    B
    `q_(2) = -60 muC`
    C
    `q_(3) = 50 muC`
    D
    `q_(4) = 10 mu C`

  • In Figure the plate A has 100 muC charge, while the plate B has 60 mu C charge. . When switch S_(2) is also closed, then.

    A
    `q_(1) = 10 mu C`
    B
    `q_(2) = -60 muC`
    C
    `q_(3) = 0 mu C`
    D
    `q_(4) = 10 mu C`

  • A parallel plate capacitor C has a charge Q. The actual charges on its plates are

    A
    Q,Q
    B
    Q/2, Q/2
    C
    Q,-Q
    D
    Q/2. - Q/2

    • Similar Questions

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