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A satellite in a force-free space sweeps...

A satellite in a force-free space sweeps stationary interplantary dust at a rate `(dM)/(dt) = beta upsilon`, where `upsilon` is the speed of escaping dust w.r.t. satellite and `M` is the mass of satellite at that instant. The acceleration of satellite is

A

`(-2alphav^(2))/(M)`

B

`(-alphav^(2))/(M)`

C

`(-alphav^(2))/(2M)`

D

`-alphav^(2)`

Text Solution

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The correct Answer is:
B
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NTA MOCK TESTS-NTA JEE MOCK TEST 42-PHYSICS
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