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A satellite in a force-free space sweeps...

A satellite in a force-free space sweeps stationary interplantary dust at a rate `(dM)/(dt) = beta upsilon`, where `upsilon` is the speed of escaping dust w.r.t. satellite and `M` is the mass of satellite at that instant. The acceleration of satellite is

A

`(-2alphav^(2))/(M)`

B

`(-alphav^(2))/(M)`

C

`(-alphav^(2))/(2M)`

D

`-alphav^(2)`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • A Satellite in a force free space sweeps stationary interplantary dust at a rate. ((dM)/(dt))=alphav . The acceleration of satellite is

    A
    `-(2alphav^(2))/(M)`
    B
    `-(alphav^(2))/(M)`
    C
    `-(alphav^(2))/(2M)`
    D
    `-alphav^(2)`

  • A satellite in force free space sweeps stationary interplanetary dust at a rate of dM//dt=alphav , where M is mass and v is the speed of satellite and alpha is a constant. The acceleration of satellite is

    A
    `(-alpha v^(2))/(2M)`
    B
    `-alpha v^(2)`
    C
    `(-2alpha v^(2))/(M)`
    D
    `(-alpha v^(2))/(M)`

  • A satellite in a force - free space sweeps stationary interplanetary dust at a rate dM//dt = alpha v , where M is the mass , v is the velocity of the satellite and alpha is a constant. What is the deacceleration of the satellite ?

    A
    ` - 2 alpha v^(2) //M`
    B
    `- alpha v^(2)//M`
    C
    `+ alpha v^(2)//M`
    D
    `-alpha v^(2)`

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