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Spin only magnetic moment of the compoun...

Spin only magnetic moment of the compound `Hg[Co(SCN)_(4)]` is `sqrt(x)` B.M. The value of 'x' is

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To find the value of 'x' in the spin-only magnetic moment of the compound `Hg[Co(SCN)_(4)]`, we will follow these steps: ### Step 1: Determine the oxidation state of cobalt in the complex The overall charge of the complex is -2. The thiocyanate ion (SCN) has a charge of -1, and there are 4 thiocyanate ions. Let the oxidation state of cobalt be \( x \). \[ x + 4(-1) = -2 \] This simplifies to: \[ x - 4 = -2 \] Solving for \( x \): \[ x = -2 + 4 = +2 \] ### Step 2: Determine the electronic configuration of Co²⁺ Cobalt (Co) has an atomic number of 27. The electronic configuration of neutral cobalt is: \[ [Ar] 3d^7 4s^2 \] For Co²⁺, we remove two electrons, which will be removed from the 4s orbital first: \[ Co^{2+} : [Ar] 3d^7 \] ### Step 3: Determine the number of unpaired electrons In the \( 3d \) subshell, there are 7 electrons. The distribution of these electrons in the five \( d \) orbitals will be: 1. Fill each orbital with one electron first (Hund's rule): - 1 electron in each of the 5 orbitals: \( \uparrow \uparrow \uparrow \uparrow \uparrow \) 2. Then start pairing: - The next two electrons will pair up in two of the orbitals. The arrangement will look like this: - Orbital 1: \( \uparrow \) - Orbital 2: \( \uparrow \) - Orbital 3: \( \uparrow \) - Orbital 4: \( \uparrow \downarrow \) - Orbital 5: \( \uparrow \downarrow \) This results in **3 unpaired electrons**. ### Step 4: Calculate the spin-only magnetic moment The formula for the spin-only magnetic moment (\( \mu \)) is given by: \[ \mu = \sqrt{n(n + 2)} \] Where \( n \) is the number of unpaired electrons. Here, \( n = 3 \): \[ \mu = \sqrt{3(3 + 2)} = \sqrt{3 \times 5} = \sqrt{15} \] ### Step 5: Determine the value of 'x' From the magnetic moment calculated, we have: \[ \mu = \sqrt{x} \text{ B.M.} \] Since we found that \( \mu = \sqrt{15} \text{ B.M.} \), we can equate: \[ \sqrt{x} = \sqrt{15} \] Squaring both sides gives: \[ x = 15 \] ### Final Answer: The value of \( x \) is **15**. ---
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