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The area (in sq. units) bounded by the c...

The area (in sq. units) bounded by the curve `f(x)=max(|x|-1, 1-|x|)` with the x- axis from `x=-1 " to " x =1` is

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To find the area bounded by the curve \( f(x) = \max(|x| - 1, 1 - |x|) \) with the x-axis from \( x = -1 \) to \( x = 1 \), we can follow these steps: ### Step 1: Understand the functions involved The function \( f(x) \) is defined as the maximum of two functions: \( |x| - 1 \) and \( 1 - |x| \). We need to analyze these two functions to determine where each is greater. ### Step 2: Analyze \( |x| - 1 \) - For \( x < -1 \): \( |x| - 1 = -x - 1 \) (which is negative). - For \( -1 \leq x < 1 \): \( |x| - 1 = 0 \) when \( x = -1 \) and \( x = 1 \); it is negative between these points. ### Step 3: Analyze \( 1 - |x| \) - For \( x < -1 \): \( 1 - |x| = 1 + x \) (which is also negative). - For \( -1 \leq x < 1 \): \( 1 - |x| \) is positive and decreases from 2 to 0 as \( x \) moves from -1 to 1. ### Step 4: Determine the intervals - From the analysis, we find that: - For \( x = -1 \): \( f(-1) = \max(0, 2) = 2 \) - For \( x = 0 \): \( f(0) = \max(-1, 1) = 1 \) - For \( x = 1 \): \( f(1) = \max(0, 0) = 0 \) ### Step 5: Sketch the graph The graph of \( f(x) \) will be: - From \( x = -1 \) to \( x = 0 \), \( f(x) = 1 - |x| \) which is a straight line from \( ( -1, 2) \) to \( (0, 1) \). - From \( x = 0 \) to \( x = 1 \), \( f(x) = 1 - |x| \) which is a straight line from \( (0, 1) \) to \( (1, 0) \). ### Step 6: Calculate the area The area under the curve from \( x = -1 \) to \( x = 1 \) can be calculated as the area of the triangle formed: - The base of the triangle is from \( x = -1 \) to \( x = 1 \) which is 2 units. - The height of the triangle is from the x-axis to the point \( (0, 1) \) which is 1 unit. Using the formula for the area of a triangle: \[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 2 \times 1 = 1 \text{ square unit} \] ### Final Answer The area bounded by the curve \( f(x) \) and the x-axis from \( x = -1 \) to \( x = 1 \) is **1 square unit**.
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