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If 4 distinct numbers are chosen randoml...

If 4 distinct numbers are chosen randomly from the first 100 natural numbers, then the probability that all 4 of them are either divisible by 3 or divisible by 5 is

A

`(.^(6)C_(4))/(^(.100)C_(4))`

B

`(.^(33)C_(4))/(.^(100)C_(4))`

C

`(.^(20)C_(4))/(.^(100)C_(4))`

D

`(.^(47)C_(4))/(.^(100)C_(4))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the probability that all 4 distinct numbers chosen from the first 100 natural numbers are either divisible by 3 or divisible by 5. Here’s a step-by-step breakdown of the solution: ### Step 1: Determine the total number of ways to choose 4 distinct numbers from 100. The total number of ways to choose 4 distinct numbers from 100 can be calculated using the combination formula: \[ \text{Total ways} = \binom{100}{4} \] ### Step 2: Count the numbers divisible by 3. To find how many numbers from 1 to 100 are divisible by 3, we can use the formula: \[ \text{Numbers divisible by 3} = \left\lfloor \frac{100}{3} \right\rfloor = 33 \] ### Step 3: Count the numbers divisible by 5. Similarly, for numbers divisible by 5: \[ \text{Numbers divisible by 5} = \left\lfloor \frac{100}{5} \right\rfloor = 20 \] ### Step 4: Count the numbers divisible by both 3 and 5 (i.e., divisible by 15). To avoid double counting, we need to find the numbers that are divisible by both 3 and 5: \[ \text{Numbers divisible by 15} = \left\lfloor \frac{100}{15} \right\rfloor = 6 \] ### Step 5: Use the principle of inclusion-exclusion to find the total numbers divisible by either 3 or 5. Using the principle of inclusion-exclusion: \[ \text{Numbers divisible by 3 or 5} = (\text{Numbers divisible by 3}) + (\text{Numbers divisible by 5}) - (\text{Numbers divisible by 15}) \] \[ = 33 + 20 - 6 = 47 \] ### Step 6: Determine the number of favorable outcomes. Now, we need to choose 4 distinct numbers from the 47 numbers that are either divisible by 3 or 5: \[ \text{Favorable ways} = \binom{47}{4} \] ### Step 7: Calculate the probability. The probability that all 4 chosen numbers are either divisible by 3 or 5 is given by: \[ \text{Probability} = \frac{\text{Favorable ways}}{\text{Total ways}} = \frac{\binom{47}{4}}{\binom{100}{4}} \] ### Step 8: Final Calculation. Now we can calculate the values of \(\binom{47}{4}\) and \(\binom{100}{4}\) to find the exact probability.
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