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A cavity of radius r is made inside a solid sphere. The volume charge density of the remaining sphere is `rho`. An electron (charge e, mass m) is released inside the cavity from point P as shown in figure. The centre of sphere and center of cavity are separated by a distance a. The time after which the electron again touches the sphere is

A

`sqrt((6sqrt2r epsilon_(0)m)/(erhoa))`

B

`sqrt((6sqrt2epsilon_(0)m)/(6rhoa))`

C

`sqrt((6repsilon_(0)m)/(erhoa))`

D

`sqrt((repsilon_(0)m)/(erhoa))`

Text Solution

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The correct Answer is:
A
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