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For a complex number Z, the equation of ...

For a complex number Z, the equation of the line of common chord of the circles `|Z-3|=2 and |Z|=2` is

A

`Z+barZ=3`

B

`Z-barZ=3`

C

`barZ-Z=3`

D

`Z+barZ+3=0`

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The correct Answer is:
To find the equation of the line of common chord of the circles given by the equations \( |Z - 3| = 2 \) and \( |Z| = 2 \), we can follow these steps: ### Step 1: Convert the equations of the circles into standard form 1. The first circle \( |Z - 3| = 2 \) can be expressed as: \[ |(x + iy) - 3| = 2 \implies |(x - 3) + iy| = 2 \] This leads to: \[ \sqrt{(x - 3)^2 + y^2} = 2 \] Squaring both sides gives: \[ (x - 3)^2 + y^2 = 4 \] Expanding this, we have: \[ x^2 - 6x + 9 + y^2 = 4 \implies x^2 + y^2 - 6x + 5 = 0 \] 2. The second circle \( |Z| = 2 \) can be expressed as: \[ |x + iy| = 2 \implies \sqrt{x^2 + y^2} = 2 \] Squaring both sides gives: \[ x^2 + y^2 = 4 \] ### Step 2: Set the equations equal to find the common chord Now we have the equations of both circles: - Circle 1: \( x^2 + y^2 - 6x + 5 = 0 \) - Circle 2: \( x^2 + y^2 - 4 = 0 \) To find the common chord, we set the left-hand sides equal to each other: \[ x^2 + y^2 - 6x + 5 = x^2 + y^2 - 4 \] Cancelling \( x^2 + y^2 \) from both sides results in: \[ -6x + 5 = -4 \] Rearranging gives: \[ -6x = -4 - 5 \implies -6x = -9 \implies 6x = 9 \implies x = \frac{3}{2} \] ### Step 3: Write the equation of the common chord Since we have found \( x = \frac{3}{2} \), we can express this in terms of the complex number \( Z \): \[ Z + \bar{Z} = 3 \] This is because \( Z = x + iy \) and \( \bar{Z} = x - iy \), thus \( Z + \bar{Z} = 2x \). ### Final Answer The equation of the line of common chord is: \[ Z + \bar{Z} = 3 \]
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