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Mole fraction of component A in vapour p...

Mole fraction of component `A` in vapour phase is `chi_(1)` and that of component `A` in liquid mixture is `chi_2`, then (`p_(A)^@`)= vapour pressure of pure A, `p_(B)^@` = vapour pressure of pure B), the total vapour pressure of liquid mixture is

A

`(P_(A)^(@)x_(1))/(x_(2))`

B

`(P_(A)^(@)x_(2))/(x_(1))`

C

`(P_(B)^(@)x_(1))/(x_(2))`

D

`(P_(B)^(@)x_(2))/(x_(1))`

Text Solution

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The correct Answer is:
B
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