If the formula of basic Beryllium nitrate is `[Be_(n)O(NO_(3))_(6)]`. What is the value of 'n' here

Answer

To determine the value of 'n' in the formula of basic Beryllium nitrate, given as \[Be_nO(NO_3)_6\], we can follow these steps:

### Step 1: Understand the Composition of Basic Beryllium Nitrate
Basic Beryllium Nitrate is a compound that contains Beryllium (Be), Oxygen (O), and Nitrate ions (NO₃). The formula indicates that there are multiple nitrate groups associated with the beryllium and oxygen.

### Step 2: Analyze the Given Formula
The formula given is \[Be_nO(NO_3)_6\]. This means that for every unit of the compound, there are 'n' Beryllium atoms, one Oxygen atom, and six Nitrate groups.

### Step 3: Determine the Ratio of Components
In the basic beryllium nitrate, the number of nitrate groups (6) suggests that there is a specific stoichiometry involving Beryllium. The basic nature of the compound typically indicates that Beryllium is present in a certain ratio to balance the charge from the nitrate ions.

### Step 4: Identify the Common Formula
From chemical knowledge, we know that the basic formula for Beryllium Nitrate can be represented as \[Be_4O(NO_3)_6\]. This indicates that for every four Beryllium atoms, there are six Nitrate groups.

### Step 5: Conclude the Value of 'n'
From the above analysis, we can conclude that the value of 'n' is 4. Thus, the formula can be rewritten as \[Be_4O(NO_3)_6\].

### Final Answer
The value of 'n' in the formula \[Be_nO(NO_3)_6\] is **4**.

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