`CH_(3)-CH_(2)-N=O and CH_(3)-CH=N-OH` are:

Options

A. Functional group isomer
B. Tautomer
C. Position isomer
D. Not an isomer

Answer

To determine the relationship between the compounds \( CH_3-CH_2-N=O \) and \( CH_3-CH=N-OH \), we need to analyze their structures and identify if they are tautomers.

### Step 1: Identify the Structures
- The first compound \( CH_3-CH_2-N=O \) can be recognized as an oxime derivative where nitrogen is bonded to an oxygen with a double bond.
- The second compound \( CH_3-CH=N-OH \) is an oxime as well, where nitrogen is bonded to a hydroxyl group.

### Step 2: Analyze the Functional Groups
- In the first compound, the nitrogen is in a +1 oxidation state due to the double bond with oxygen.
- In the second compound, nitrogen is bonded to a hydroxyl group, which indicates a different oxidation state and functional group arrangement.

### Step 3: Determine Tautomerism
- Tautomerism is a type of isomerism where isomers (tautomers) readily interconvert, typically involving the relocation of a hydrogen atom and a shift in bonding.
- In this case, the hydrogen atom can shift from the nitrogen in the first compound to the nitrogen in the second compound, leading to the formation of the other compound.

### Step 4: Conclusion
- Since both compounds can interconvert through the transfer of a hydrogen atom, they are classified as tautomers.

Thus, the answer to the question is that \( CH_3-CH_2-N=O \) and \( CH_3-CH=N-OH \) are **tautomers**.