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The gravitational force acting on a part...

The gravitational force acting on a particle due to a solid sphere of uniform density and radius R, at a distance of 3R from the center of the sphere is `F_1` . A spherical hole of radius (R/2) is now made in the sphere as shown in the figure . The sphere with hole now exert a force `F_2` on the same particle , Ratio of `F_1 and F_2` is

A

`(9)/(50)`

B

`(41)/(50)`

C

`(3)/(25)`

D

`(22)/(25)`

Text Solution

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The correct Answer is:
B
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