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Here how many ligands are ambidentate? ...

Here how many ligands are ambidentate?
`CN^(-), ONO^(-), S_(2)O_(3)^(2-), CNO^(-), C_(2)O_(4)^(2-), CH_(3)COO^(-)en`

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The correct Answer is:
To determine how many ligands from the given list are ambidentate, we need to analyze each ligand to identify if they have more than one donor atom capable of coordinating with a metal ion, but can only bind through one of those donor atoms at a time. ### Step-by-Step Solution: 1. **Identify the Ligands**: The ligands provided are: - CN^(-) - ONO^(-) - S2O3^(2-) - CNO^(-) - C2O4^(2-) - CH3COO^(-) - en (ethylenediamine) 2. **Define Ambidentate Ligands**: Ambidentate ligands are those that can coordinate to a metal through more than one atom, but only one atom at a time. 3. **Analyze Each Ligand**: - **CN^(-)**: Has carbon (C) and nitrogen (N) as potential donor atoms. It can bind through either C or N. **(Ambidentate)** - **ONO^(-)**: Contains oxygen (O) and nitrogen (N) as donor atoms. It can bind through either O or N. **(Ambidentate)** - **S2O3^(2-)**: Contains sulfur (S) and oxygen (O). It can bind through S or O. **(Ambidentate)** - **CNO^(-)**: Contains carbon (C) and oxygen (O) as donor atoms. It can bind through either C or O. **(Ambidentate)** - **C2O4^(2-)**: Contains two carbonyl groups (C=O) and can bind through either of the oxygen atoms, but both donor atoms are adjacent. **(Bidentate, not ambidentate)** - **CH3COO^(-)**: Contains a carboxylate group (COO^(-)), which can bind through the carbon (C) or one of the oxygens (O). **(Ambidentate)** - **en (ethylenediamine)**: Contains two nitrogen atoms, but both are the same type of donor atom. **(Bidentate, not ambidentate)** 4. **Count the Ambidentate Ligands**: From the analysis, the ambidentate ligands are: - CN^(-) - ONO^(-) - S2O3^(2-) - CNO^(-) - CH3COO^(-) Thus, there are **5 ambidentate ligands**. ### Final Answer: **5 ambidentate ligands.**
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