In input in a full - wave rectifier is `e=50 sin(314t)" volt"`, diode resistance is `100Omega` and load resistance is `1kOmega` then, pulse frequency of output voltage is

Options

A. 50 Hz
B. 100 Hz
C. 150 Hz
D. 200 Hz

Answer

To solve the problem, we need to determine the pulse frequency of the output voltage from a full-wave rectifier given the input voltage.

### Step-by-Step Solution:

1. **Identify the Input Voltage**:
The input voltage is given as \( e = 50 \sin(314t) \) volts.

2. **Determine the Angular Frequency (\( \omega \))**:
From the equation \( e = A \sin(\omega t) \), we can identify that \( \omega = 314 \) rad/s.

3. **Calculate the Frequency (\( f \))**:
The relationship between angular frequency and frequency is given by:
\[ \omega = 2\pi f \]
Rearranging this gives:
\[ f = \frac{\omega}{2\pi} \]
Substituting the value of \( \omega \):
\[ f = \frac{314}{2\pi} \approx \frac{314}{6.28} \approx 50 \text{ Hz} \]

4. **Determine the Output Frequency**:
In a full-wave rectifier, the output frequency is double that of the input frequency. Therefore:
\[ f_{\text{output}} = 2 \times f_{\text{input}} = 2 \times 50 \text{ Hz} = 100 \text{ Hz} \]

5. **Conclusion**:
The pulse frequency of the output voltage is \( 100 \text{ Hz} \).

### Final Answer:
The pulse frequency of the output voltage is **100 Hz**.