Name the end product in the following series of reaction
`CH_3COOHoverset(NH_3)(rarr)A overset(Delta)(rarr) B overset(P_2O_5)(rarr) C`

Options

A. `CH_4`
B. `CH_3OH`
C. `Acetonitrile
D. ammonium acetate

Answer

To solve the problem step by step, we will analyze the reactions involving acetic acid (CH₃COOH) and determine the end product.

### Step 1: Identify the initial reaction
The first reaction involves acetic acid (CH₃COOH) reacting with ammonia (NH₃). This is an acid-base reaction where acetic acid donates a proton (H⁺) to ammonia.

**Reaction:**
\[ \text{CH}_3\text{COOH} + \text{NH}_3 \rightarrow \text{CH}_3\text{COO}^- \text{NH}_4^+ \]

**Product A:**
The product formed is ammonium acetate (CH₃COO⁻NH₄⁺).

### Step 2: Heating the product
Next, we heat the ammonium acetate (Product A). During heating, a dehydration reaction occurs where one molecule of water (H₂O) is eliminated.

**Reaction:**
\[ \text{CH}_3\text{COO}^- \text{NH}_4^+ \xrightarrow{\Delta} \text{CH}_3\text{CO} \text{NH}_2 + \text{H}_2\text{O} \]

**Product B:**
The product formed after heating is acetamide (CH₃CONH₂).

### Step 3: Reaction with P₂O₅
The next step involves treating acetamide (Product B) with phosphorus pentoxide (P₂O₅), which is a strong dehydrating agent. This will again lead to the elimination of a water molecule.

**Reaction:**
\[ \text{CH}_3\text{CONH}_2 \xrightarrow{\text{P}_2\text{O}_5} \text{CH}_3\text{CN} + \text{H}_2\text{O} \]

**Product C:**
The final product formed is acetonitrile (CH₃CN).

### Conclusion
The end product of the series of reactions is acetonitrile (CH₃CN).

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