`CH_(3)-CH=CH-CHOH-CH_(3)overset("Jones")underset("reagent")rarr`
Product is ?

Options

A. `CH_(3)-CH_(2)-CH_(2)-underset(O)underset(||)C-CH_(3)`
B. `CH_(3)-CH=CH-underset(O)underset(||)C-CH_(3)`
C. `CH_(3)-CH_(2)-CH_(2)-underset(OH)underset("| ")"CH"-CH_(3)`
D. `CH_(3)-CH_(2)-COOH`

Answer

To solve the problem of what product is formed when the compound \( CH_3-CH=CH-CHOH-CH_3 \) is treated with Jones reagent, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compound**: The given compound is \( CH_3-CH=CH-CHOH-CH_3 \). It contains a double bond and a hydroxyl (OH) group.

2. **Understand the Jones Reagent**: The Jones reagent is a solution of chromium trioxide (CrO₃) in an acidic medium (usually sulfuric acid, H₂SO₄). It is used to oxidize alcohols.

3. **Determine the Type of Alcohol**: In the compound, the -OH group is attached to a carbon that is also connected to a double bond. This makes it a secondary alcohol because the carbon with the -OH group is bonded to two other carbon atoms.

4. **Oxidation Reaction**: When a secondary alcohol is treated with Jones reagent, it gets oxidized to a ketone. The oxidation process involves the removal of hydrogen from the hydroxyl group and the adjacent carbon, leading to the formation of a carbonyl group (C=O).

5. **Identify the Product**: In this case, the secondary alcohol \( CH_3-CHOH-CH_3 \) will be oxidized to form a ketone. The structure of the product will be \( CH_3-CO-CH_3 \), which is acetone.

6. **Final Product**: Therefore, the product formed from the reaction of \( CH_3-CH=CH-CHOH-CH_3 \) with Jones reagent is **acetone**.

### Conclusion:
The final product is **acetone** (or 2-propanone).