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Four particles A, B, and C and D of mass...

Four particles A, B, and C and D of masses `m_(A), m_(B), m_(B) and m_(D)` respectively, follow the paths shown in the figure, in a uniform magnetic field. Each particle moving with same speed. `Q_(A), Q_(B), Q_(C) and Q_(D)` are the specific charge of particles A, B, C and D respectively (assume that the motion of each particle is in the same plane perpendicular to the magnetic field).

A

`Q_(A) lt Q_(B) lt Q_(C) lt Q_(D)`

B

`Q_(B) lt Q_(D) lt Q_(C) ltQ_(A)`

C

charge on the particle B and particle D is of the same nature

D

work done by magnetic force on the particle C is minimum as compared to other particles

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • Two particle A and B of masses m_(A) and m_(B) respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are v_(A) and v_(B) respectively and the trajectories are as shown in the figure. Then-

    A
    `m_(A) v_(A) lt m_(B)v_(B)`
    B
    `m_(A)v_(A) gt m_(B) v_(B)`
    C
    `m_(A) lt m_(B) and v_(A) lt v_(B)`
    D
    `m_(A) = m_(B) and v_(A) = v_(B)`

  • Two particles A and B of masses m_(A)andm_(B) respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are v_(A)andv_(B) respectively and the trajectories are as shown in the figure. Then -

    A
    `m_(A)v_(A)ltm_(B)v_(B)`
    B
    `m_(A)v_(A)gtm_(B)v_(B)`
    C
    `m_(A)ltm_(B)andv_(A)ltv_(B)`
    D
    `m_(A)=m_(B)andv_(A)=v_(B)`

  • Two particles A and B of masses m_A and m_B respectively and having the same charge are moving ina plane. A uniform magnetic field exists perependicular to this plane. The speeds of the particles are v_A and v_B respectively and the trajectories are as shown in the figure. Then,

    A
    `m_Av_Altm_Bv_B`
    B
    `m_Av_Agtm_Bv_B`
    C
    `m_Altm_B and v_Altv_B`
    D
    `m_A=m_B and v_A=v_B`

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