The final product in the following reaction sequence is
p - chloroaniline `underset(0-5^@C)overset(NaNO_2,HCl)rarroverset(KCN ?)rarroverset(LiAlH_4 ?)rarr`

Options

A. p - chlorophenol
B. p - chlorobenzamide
C. p - chlorobenzylamine
D. p - chlorobenzyl alcohol

Answer

To determine the final product of the reaction sequence starting from p-chloroaniline, we will go through the steps outlined in the video transcript.

### Step 1: Formation of Diazonium Salt
- **Starting Material**: p-Chloroaniline (C6H4ClNH2)
- **Reagents**: NaNO2 and HCl at 0-5°C
- **Reaction**: The amino group (NH2) of p-chloroaniline is converted into a diazonium salt.
- **Product**: The product formed is p-Chloro-benzenediazonium chloride (C6H4ClN2Cl).

### Step 2: Reaction with KCN
- **Reagents**: KCN
- **Reaction**: The diazonium salt reacts with KCN. The cyanide ion (CN-) attacks the diazonium salt, leading to the release of nitrogen gas (N2).
- **Product**: The product formed is p-Chloro-benzene-cyanide (C6H4ClCN).

### Step 3: Reduction with LiAlH4
- **Reagents**: LiAlH4
- **Reaction**: The cyanide group (CN) is reduced by LiAlH4 to form an amine.
- **Product**: The final product is p-Chloro-benzylamine (C6H4ClCH2NH2).

### Final Product
The final product of the reaction sequence is **p-Chloro-benzylamine**.

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