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The sequence of N - bass in one strand ...

The sequence of N - bass in one strand DNA is ' 3 TAC CAC TCC ATA ATT 5 ' How many purines will be present in the Watson crick structure of this DNA ?

A

18

B

5

C

15

D

10

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The correct Answer is:
To determine the number of purines present in the Watson-Crick structure of the given DNA sequence, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the DNA Strand**: The given DNA sequence is '3 TAC CAC TCC ATA ATT 5'. This is the sequence of one strand of DNA. 2. **Determine the Complementary Strand**: According to the Watson-Crick base pairing rules: - Adenine (A) pairs with Thymine (T) - Guanine (G) pairs with Cytosine (C) We need to find the complementary strand for the given sequence. The complementary bases for each nucleotide in the given strand will be: - T pairs with A - A pairs with T - C pairs with G - C pairs with G - A pairs with T - T pairs with A - C pairs with G - C pairs with G - A pairs with T - A pairs with T - T pairs with A Therefore, the complementary strand (from 5' to 3') will be: '5 ATG GTG AGG TAT TAA 3'. 3. **Count Purines in the Original Strand**: Purines are adenine (A) and guanine (G). Now, we will count the number of purines in the original strand '3 TAC CAC TCC ATA ATT 5': - T: 3 - A: 4 - C: 5 - G: 0 From the original strand, we have: - Adenine (A): 4 - Guanine (G): 0 Total purines = 4 (A) + 0 (G) = 4. 4. **Count Purines in the Complementary Strand**: Now let's count the purines in the complementary strand '5 ATG GTG AGG TAT TAA 3': - A: 5 - G: 3 Total purines = 5 (A) + 3 (G) = 8. 5. **Final Count of Purines in the Watson-Crick Structure**: The total number of purines in the Watson-Crick structure (both strands combined) is: - Original strand purines: 4 - Complementary strand purines: 8 - Total purines = 4 + 8 = 12. ### Final Answer: The total number of purines present in the Watson-Crick structure of this DNA is **12**.
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