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A Bohr's hydrogen atom undergoes a trans...

A Bohr's hydrogen atom undergoes a transition `n = 5 to n = 4` and emits a photon of frequency `f`. Frequency of circular motion of electron in `n = 4` orbit is `f_(4)`. The ratio `f//f_(4)` is found to be `18//5 m`. State the value of `m`.

A

`18/25`

B

`16/25`

C

`9/25`

D

`8/25`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If in hydrogen atom, radius of n^(th) Bohr orbit is r_n ., frequency of revolution of electron in n^(th) orbit is f_n choose the correct option.

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    Both (a) and (b)

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  • In hydrogen atom electron jumps from (n+1)th state to nth state the frequency of emitted photon is directly proportional to (n>>1)

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