An individual having genotype AaBBccDD will product ………..... Types of gametes.

Options

A. 2
B. 4
C. 8
D. 16

Answer

To determine the number of types of gametes produced by an individual with the genotype AaBBccDD, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotype**: The given genotype is AaBBccDD.

2. **Determine Heterozygous Genes**:
- A is heterozygous (Aa).
- B is homozygous dominant (BB).
- C is homozygous recessive (cc).
- D is homozygous dominant (DD).

3. **Count the Heterozygous Genes**:
- In this genotype, only the A gene is in a heterozygous condition. Therefore, there is **1 heterozygous gene**.

4. **Use the Formula for Gametes**:
- The formula to calculate the number of types of gametes is \(2^n\), where \(n\) is the number of heterozygous genes.
- Here, \(n = 1\).

5. **Calculate the Number of Gametes**:
- Substitute \(n\) into the formula:
\[ \text{Number of gametes} = 2^1 = 2. \]

6. **List the Types of Gametes**:
- The two types of gametes produced will be:
- One gamete with the alleles: A, B, c, D (capital A, capital B, small c, capital D).
- The other gamete with the alleles: a, B, c, D (small a, capital B, small c, capital D).

### Final Answer:
The individual will produce **2 types of gametes**.

---