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The radius of hydrogen atom in its groun...

The radius of hydrogen atom in its ground state is `5.3 xx 10^(-11)m`. After collision with an electron it is found to have a radius of `21.2 xx 10^(-11)m`. What is the principle quantum number of `n` of the final state of the atom ?

A

n = 4

B

n = 2

C

n = 16

D

n = 3

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • The radius of hydrogen atom in its ground state is 5.3 xx 10^-11 m . After collision with an electron it is found to have a radius of 21.2 xx 10^-11 m . The principal quantum number of the final state of the atom is.

    A
    2
    B
    3
    C
    4
    D
    5

  • The radius of hydrogen atom, in its ground state, is of the order of

    A
    `10^(-8)` cm
    B
    `10^(-6)` cm
    C
    `10^(-5)` cm
    D
    `10^(-4)` cm

  • The radius of H atom in its ground state is 0.53 Å After collision with an electron, its radius is found to be 21.2 xx 10^(-11)m . In this state, the principle quantum number 'n' of the H-atom is

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    2
    B
    3
    C
    4
    D
    16

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