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When a metallic surface is illuminated w...

When a metallic surface is illuminated with monochromatic light of wavelength `lambda`, the stopping potential is `5 V_0`. When the same surface is illuminated with the light of wavelength `3lambda`, the stopping potential is `V_0`. Then, the work function of the metallic surface is

A

`(hc)/(6lamda)`

B

`(hc)/(5lamda)`

C

`(hc)/(4lamda)`

D

`(2hc)/(4lamda)`

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The correct Answer is:
A
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