Which colour precipitate is obtained by reaction of phosphate radical with ammonium molybdate

Options

A. Green
B. Pink
C. Canary yellow
D. Violet

Answer

To determine the color of the precipitate formed when phosphate reacts with ammonium molybdate, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are phosphate ions (PO4^3-) and ammonium molybdate ((NH4)2MoO4).

2. **Understand the Reaction Conditions**:
The reaction typically occurs in the presence of nitric acid (HNO3), which helps to maintain the acidic environment necessary for the formation of the precipitate.

3. **Write the Chemical Reaction**:
The phosphate ions will react with ammonium molybdate to form a complex. The general reaction can be represented as:
\[ PO_4^{3-} + (NH_4)_2MoO_4 \rightarrow \text{Precipitate} \]

4. **Determine the Nature of the Precipitate**:
The precipitate formed from this reaction is a complex of molybdenum and phosphate, specifically ammonium phosphomolybdate.

5. **Identify the Color of the Precipitate**:
The precipitate formed is known to be canary yellow in color. This is a characteristic color of the ammonium phosphomolybdate complex.

6. **Conclusion**:
Therefore, the color of the precipitate obtained from the reaction of phosphate with ammonium molybdate is canary yellow.

### Final Answer:
The color of the precipitate obtained from the reaction of phosphate radical with ammonium molybdate is **canary yellow**.