In mollusks of New York state, which of these experiences gives you a value between 0.1 to 0.2?
( S = log of species richness, A = log of Area, C = log of Y- intercept in the species richness area curve)

Options

A. `(S-C)/A`
B. `(S-A)/C`
C. `(C-A)/S`
D. `(A-S)/C`

Answer

To solve the question regarding the values in mollusks of New York state and their relationship with species richness, area, and the y-intercept in the species-area curve, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Variables**:
- **S**: log of species richness
- **A**: log of area
- **C**: log of y-intercept in the species richness-area curve

2. **Species-Area Relationship**:
- The species-area relationship can be expressed as:
\[ S = C + Z \cdot A \]
- Here, Z represents the slope of the line in the log-log plot of species richness against area.

3. **Identify the Range for Z**:
- According to the information provided, the value of Z (the slope) typically falls between 0.1 and 0.2 for specific taxonomic groups in a defined area.

4. **Rearranging the Equation**:
- To find Z, we can rearrange the species-area relationship equation:
\[ Z = \frac{S - C}{A} \]
- This means that Z can be calculated if we know the values of S, C, and A.

5. **Conclusion**:
- Since the question asks for a value that falls between 0.1 and 0.2, we conclude that Z, which represents the slope of the species-area relationship curve for mollusks in New York state, is the value that fits this criterion.

### Final Answer:
The value that experiences a range between 0.1 to 0.2 in mollusks of New York state is **Z** (the slope of the species-area relationship).

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