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A man of mass 60 kg climbed down using a...

A man of mass 60 kg climbed down using an elevator . The elevator had an acceleration of `4ms^(-2)` . If the acceleration due to gravity is `10 ms ^(-2)` , the man's apparent weight on his way down is

A

60 N

B

240 N

C

360 N

D

840 N

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The correct Answer is:
To find the man's apparent weight while he is descending in the elevator, we can follow these steps: ### Step 1: Identify the Forces Acting on the Man When the man is in the elevator, two main forces act on him: 1. The gravitational force (weight) acting downward, which is given by \( W = mg \). 2. The normal force (apparent weight) acting upward from the elevator floor. ### Step 2: Calculate the Weight of the Man The weight of the man can be calculated using the formula: \[ W = mg \] where: - \( m = 60 \, \text{kg} \) (mass of the man) - \( g = 10 \, \text{m/s}^2 \) (acceleration due to gravity) Substituting the values: \[ W = 60 \, \text{kg} \times 10 \, \text{m/s}^2 = 600 \, \text{N} \] ### Step 3: Consider the Acceleration of the Elevator The elevator is accelerating downward with an acceleration of \( a = 4 \, \text{m/s}^2 \). When the elevator accelerates downward, the apparent weight of the man will be less than his actual weight. ### Step 4: Apply Newton's Second Law In the frame of reference of the elevator, the net force acting on the man can be expressed as: \[ N - mg = -ma \] where: - \( N \) is the normal force (apparent weight), - \( m \) is the mass of the man, - \( g \) is the acceleration due to gravity, - \( a \) is the acceleration of the elevator. Rearranging the equation gives: \[ N = mg - ma \] ### Step 5: Substitute the Values Now, substituting the known values into the equation: \[ N = mg - ma = m(g - a) \] Substituting \( m = 60 \, \text{kg} \), \( g = 10 \, \text{m/s}^2 \), and \( a = 4 \, \text{m/s}^2 \): \[ N = 60 \, \text{kg} \times (10 \, \text{m/s}^2 - 4 \, \text{m/s}^2) \] \[ N = 60 \, \text{kg} \times 6 \, \text{m/s}^2 = 360 \, \text{N} \] ### Conclusion The man's apparent weight while he is descending in the elevator is \( 360 \, \text{N} \). ---
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