Find the end product in the given sequence of reaction `HC-=CHoverset(1%HgSO_4)rarrAoverset(CH_3MgX)rarrBoverset([O])rarr`

Options

A. Ethanol
B. Acetic acid
C. Acetone
D. Isopropyl alcohol

Answer

To solve the given sequence of reactions, we will follow each step carefully:

1. **Starting Material**: The reaction begins with an alkyne, specifically ethyne (HC≡CH).

2. **Reaction with Mercury(II) Sulfate**:
- When ethyne reacts with 1% HgSO₄, it undergoes hydration to form an enol intermediate.
- The reaction can be represented as:
\[ HC≡CH + H₂O \overset{HgSO₄}{\rightarrow} CH₃CHO \text{ (enol form)} \]
- The enol form then tautomerizes to the corresponding ketone (keto form), which is acetaldehyde (CH₃CHO).

3. **Formation of Product A**:
- The product A from this reaction is acetaldehyde (CH₃CHO).

4. **Reaction with Grignard Reagent**:
- Next, we react acetaldehyde with a Grignard reagent, which we can assume is methylmagnesium halide (CH₃MgX).
- The Grignard reagent acts as a nucleophile and attacks the carbonyl carbon of acetaldehyde:
\[ CH₃CHO + CH₃MgX \rightarrow CH₃CH(OH)CH₃ \text{ (propan-2-ol)} \]
- This results in the formation of an alcohol (propan-2-ol) after the addition of water and elimination of the magnesium salt.

5. **Formation of Product B**:
- The product B from this reaction is propan-2-ol (CH₃CH(OH)CH₃).

6. **Oxidation of Product B**:
- Finally, we oxidize propan-2-ol. The oxidation of secondary alcohols typically leads to the formation of ketones:
\[ CH₃CH(OH)CH₃ \overset{[O]}{\rightarrow} CH₃COCH₃ \text{ (acetone)} \]
- The end product after oxidation is acetone (CH₃COCH₃).

**Final Answer**: The end product of the given sequence of reactions is acetone (CH₃COCH₃).