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The de-Brogile wavelength of a neutron a...

The de-Brogile wavelength of a neutron at `927^(@)`C is `lamda`. What will be its wavelength at `27^(@)`C?

A

`lamda//2`

B

`lamda`

C

`2lamda`

D

`4lamda`

Text Solution

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The correct Answer is:
C
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