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The pH of aqueous solution of magnesium ...

The pH of aqueous solution of magnesium hydroxide is 9.0 . If `K_(sp)` of magnesium hydroxide is `1.0xx10^(-11) M^(3)` , then the concentration of magnesium ions in the solution is

A

`10^(-7) M`

B

`10^(-2)M`

C

`0.1 M`

D

`10^(-6)M`

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The correct Answer is:
To find the concentration of magnesium ions in the solution, we can follow these steps: ### Step 1: Calculate the concentration of hydroxide ions (OH⁻) Given that the pH of the solution is 9.0, we can find the concentration of hydrogen ions (H⁺) using the formula: \[ \text{pH} = -\log[H^+] \] To find [H⁺]: \[ [H^+] = 10^{-\text{pH}} = 10^{-9} \, \text{M} \] ### Step 2: Calculate the concentration of hydroxide ions (OH⁻) Using the ion product of water at 25°C, where \(K_w = [H^+][OH^-] = 1.0 \times 10^{-14}\): \[ [OH^-] = \frac{K_w}{[H^+]} = \frac{1.0 \times 10^{-14}}{10^{-9}} = 1.0 \times 10^{-5} \, \text{M} \] ### Step 3: Write the dissociation equation for magnesium hydroxide The dissociation of magnesium hydroxide (Mg(OH)₂) in water can be represented as: \[ \text{Mg(OH)}_2 \rightleftharpoons \text{Mg}^{2+} + 2\text{OH}^- \] Let the concentration of magnesium ions, [Mg²⁺], be \(x\). Then, the concentration of hydroxide ions will be \(2x\). ### Step 4: Set up the expression for \(K_{sp}\) The solubility product constant (\(K_{sp}\)) for magnesium hydroxide is given by: \[ K_{sp} = [Mg^{2+}][OH^-]^2 \] Substituting the values we have: \[ K_{sp} = x \cdot (1.0 \times 10^{-5})^2 \] ### Step 5: Substitute the value of \(K_{sp}\) Given that \(K_{sp} = 1.0 \times 10^{-11}\): \[ 1.0 \times 10^{-11} = x \cdot (1.0 \times 10^{-5})^2 \] ### Step 6: Solve for \(x\) Calculating \( (1.0 \times 10^{-5})^2 \): \[ (1.0 \times 10^{-5})^2 = 1.0 \times 10^{-10} \] Now substituting back: \[ 1.0 \times 10^{-11} = x \cdot 1.0 \times 10^{-10} \] Solving for \(x\): \[ x = \frac{1.0 \times 10^{-11}}{1.0 \times 10^{-10}} = 0.1 \, \text{M} \] ### Conclusion The concentration of magnesium ions \([Mg^{2+}]\) in the solution is: \[ \text{[Mg}^{2+}] = 0.1 \, \text{M} \] ---
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