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Plotting log(10)t(1//2) against log (10)...

Plotting `log_(10)t_(1//2)` against `log _(10)[A_0]` (where `A_0` is the initial concentration of a reactant) for a fist order reaction the slope will be

A

`-2`

B

Zero

C

`+1`

D

`-1`

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The correct Answer is:
B
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