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An olefinic compound on reductive ozonol...

An olefinic compound on reductive ozonolysis produces formaldehyde, acetaldehyde and 1, 3-propanedial. The IUPAC name of the alkene is

A

1, 4-Hexadiene

B

2-Methyl-1, 3-pentadiene

C

1, 2-Hexadiene

D

None of these

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The correct Answer is:
To determine the IUPAC name of the alkene that produces formaldehyde, acetaldehyde, and 1,3-propanediol upon reductive ozonolysis, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Products**: The products of the reductive ozonolysis are: - Formaldehyde (HCHO) - Acetaldehyde (CH3CHO) - 1,3-Propanediol (which is HOCH2CHOHCHO) 2. **Identify the Structure of the Products**: - Formaldehyde is a 1-carbon aldehyde. - Acetaldehyde is a 2-carbon aldehyde. - 1,3-Propanediol has two aldehyde groups at the ends, indicating that the original alkene likely had a structure that could lead to these products upon cleavage. 3. **Determine the Alkene Structure**: - The ozonolysis reaction involves breaking the double bond of the alkene and forming carbonyl groups (C=O). - The presence of both formaldehyde and acetaldehyde suggests that the alkene has a structure that allows for the formation of these aldehydes. 4. **Construct Possible Alkene**: - Given the products, we can deduce that the alkene must have a structure that allows for the formation of these carbonyl compounds. - The alkene must be symmetrical to produce both formaldehyde and acetaldehyde. 5. **Visualize the Alkene**: - The alkene can be represented as follows: - CH2=CH-CH2-CH=CH2 - This structure can be rearranged to show how it would break down into the products. 6. **Number the Carbon Chain**: - Number the carbon chain from one end to determine the positions of the double bonds. - The double bonds are located at the 1st and 4th positions. 7. **IUPAC Naming**: - The IUPAC name for the alkene with double bonds at positions 1 and 4 is 1,4-hexadiene. 8. **Conclusion**: - Therefore, the IUPAC name of the alkene that produces the given products upon reductive ozonolysis is **1,4-hexadiene**. ### Final Answer: The IUPAC name of the alkene is **1,4-hexadiene**.
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