Tertiary butyl alcohol gives tertiary butyl chloride on treatment with

Options

A. Conc. HCl/anhydrous `ZnCl_2`
B. KCN
C. NaOCl
D. `Cl_2`

Answer

To determine which compound gives tertiary butyl chloride when treated with tertiary butyl alcohol, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Tertiary Butyl Alcohol**:
- Tertiary butyl alcohol (also known as 2-methylpropan-2-ol) has the structure:
\[ \text{(CH}_3\text{)}_3\text{COH} \]
- This means it has three methyl groups (CH₃) attached to a central carbon atom that is also bonded to a hydroxyl group (OH).

2. **Understand the Reaction**:
- Tertiary butyl alcohol can be converted into tertiary butyl chloride through a substitution reaction where the hydroxyl group (OH) is replaced by a chlorine atom (Cl).
- This reaction typically occurs in the presence of a reagent that can provide the chloride ion (Cl⁻).

3. **Identify the Reagent**:
- A common reagent used for this transformation is hydrochloric acid (HCl) or thionyl chloride (SOCl₂).
- In the presence of HCl, the hydroxyl group of the alcohol is protonated, making it a better leaving group, and then it is replaced by the chloride ion.

4. **Write the Reaction**:
- The reaction can be written as:
\[ \text{(CH}_3\text{)}_3\text{COH} + \text{HCl} \rightarrow \text{(CH}_3\text{)}_3\text{CCl} + \text{H}_2\text{O} \]
- Here, tertiary butyl alcohol reacts with hydrochloric acid to form tertiary butyl chloride and water.

5. **Conclusion**:
- Tertiary butyl alcohol gives tertiary butyl chloride when treated with hydrochloric acid (HCl).