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Radius of .2^4 He nucleus is 3 Fermi. Th...

Radius of `._2^4 He` nucleus is `3` Fermi. The radius of `._82^206 Pb` nucleus will be.

A

5 fermi

B

6 fermi

C

11.16 fermi

D

8 fermi

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • Radius of ._2^4He The nucleus is 3 Fermi. The radius of ._16^32S nucleus will be

    A
    6 Fermi
    B
    4 Fermi
    C
    5 Fermi
    D
    8 Fermi

  • The radius of Al_(23)^(27) nucleus will be :

    A
    `1.2 xx 10^(-15)m`
    B
    `27 xx 10^(-15)m`
    C
    `10.8 xx 10^(-15)m`
    D
    `3.6 xx 10^(-15)m`

  • If the radius of a nucleus ""^(256) X is 8 fermi , then the radius of ""^(4) He nucleus will be

    A
    16 fermi
    B
    2 fermi
    C
    32 fermi
    D
    4 fermi

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