The set of four quantum number not possible from the following .

Options

A. `n = 3 , l =0, m = 0 , s = -1/2`
B. `n = 3 , l =2, m = 0 , s = -1/2`
C. `n = 3 , l =3, m = -3 , s = -1/2`
D. `n = 3 , l =2, m = -2 , s = -1/2`

Answer

To determine which set of quantum numbers is not possible, we need to analyze each set based on the rules governing quantum numbers.

### Step-by-Step Solution:

1. **Understanding Quantum Numbers**:
- The principal quantum number (n) indicates the energy level or shell.
- The azimuthal quantum number (l) indicates the subshell and can take values from 0 to (n-1).
- The magnetic quantum number (m) can take values from -l to +l, including 0.
- The spin quantum number (s) can be +1/2 or -1/2.

2. **Analyzing Each Set**:
- **Set 1**: n = 3, l = 0, m = 0
- For n = 3, l can be 0, 1, or 2.
- Since l = 0 is valid, and m = 0 is also valid for l = 0, this set is possible.

- **Set 2**: n = 3, l = 2, m = 0
- For n = 3, l can be 0, 1, or 2.
- Since l = 2 is valid, m can take values -2, -1, 0, 1, or 2. Thus, m = 0 is valid. This set is possible.

- **Set 3**: n = 3, l = 3
- For n = 3, l can only be 0, 1, or 2.
- l = 3 is not valid. Therefore, this set is not possible.

- **Set 4**: n = 3, l = 2, m = -2
- For n = 3, l = 2 is valid.
- For l = 2, m can take values -2, -1, 0, 1, or 2. Thus, m = -2 is valid. This set is possible.

3. **Conclusion**:
- The only set of quantum numbers that is not possible is **Set 3: n = 3, l = 3**.

### Final Answer:
The set of quantum numbers that is not possible is **n = 3, l = 3**.