The input signal is given to a CE amplifier having a voltage gain of 150 is `V_i = 2cos (15t+pi/3)` The corresponding output signal will be :

Options

A. `75cos(15t+(2pi)/3)`
B. `2cos(15t+(5pi)/6)`
C. `300cos(15t+(4pi)/3)`
D. `300cos(15t+(pi)/3)`

Answer

To find the corresponding output signal of a common emitter (CE) amplifier given the input signal and the voltage gain, we can follow these steps:

### Step 1: Identify the Input Signal and Voltage Gain
The input signal is given as:
\[ V_i = 2 \cos(15t + \frac{\pi}{3}) \]
The voltage gain of the CE amplifier is:
\[ A_v = 150 \]

### Step 2: Calculate the Output Voltage
The output voltage \( V_o \) can be calculated using the formula:
\[ V_o = A_v \times V_i \]
Substituting the values we have:
\[ V_o = 150 \times (2 \cos(15t + \frac{\pi}{3})) \]

### Step 3: Simplify the Output Voltage
Now, we can simplify the output voltage:
\[ V_o = 150 \times 2 \cos(15t + \frac{\pi}{3}) \]
\[ V_o = 300 \cos(15t + \frac{\pi}{3}) \]

### Step 4: Adjust for Phase Shift
In a common emitter amplifier, the output signal is inverted, which means there is a phase shift of 180 degrees (or \( \pi \) radians). Therefore, we need to add \( \pi \) to the phase of the output signal:
\[ V_o = 300 \cos(15t + \frac{\pi}{3} + \pi) \]
This can be rewritten as:
\[ V_o = 300 \cos(15t + \frac{\pi}{3} + \frac{3\pi}{3}) \]
\[ V_o = 300 \cos(15t + \frac{4\pi}{3}) \]

### Final Output Signal
Thus, the corresponding output signal is:
\[ V_o = 300 \cos(15t + \frac{4\pi}{3}) \]