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For a real gas obeying van der waal's eq...

For a real gas obeying van der waal's equation , graph is plotted between `PV_m` (y- axis) and P (x - axis) where `V_m` is molar volume . Y - intercept the graph is

A

RT

B

`(P+a/V^2)`

C

`(RT)/(V-b)`

D

Cannot be determined

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The correct Answer is:
To find the y-intercept of the graph plotted between \( PV_m \) (y-axis) and \( P \) (x-axis) for a real gas obeying van der Waals equation, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the van der Waals Equation**: The van der Waals equation for one mole of a real gas is given by: \[ \left( P + \frac{a}{V_m^2} \right)(V_m - b) = RT \] Where: - \( P \) = pressure - \( V_m \) = molar volume - \( R \) = universal gas constant - \( T \) = temperature - \( a \) and \( b \) are van der Waals constants. 2. **Rearranging the Equation**: For one mole, we can rearrange the van der Waals equation to express \( PV_m \): \[ P V_m = RT - P b - \frac{a}{V_m} \] 3. **Graphing \( PV_m \) vs. \( P \)**: We need to express \( PV_m \) in terms of \( P \): \[ PV_m = RT - Pb - \frac{a}{V_m} \] This implies that \( PV_m \) is a function of \( P \). 4. **Finding the y-intercept**: To find the y-intercept of the graph, we need to consider the case when \( P = 0 \): \[ PV_m = RT - 0 \cdot b - \frac{a}{V_m} \quad \text{(as \( P \) approaches 0)} \] Therefore, the y-intercept (when \( P = 0 \)) is: \[ PV_m = RT \] 5. **Conclusion**: Thus, the y-intercept of the graph of \( PV_m \) vs. \( P \) is: \[ \text{Y-intercept} = RT \] ### Final Answer: The y-intercept of the graph is \( RT \).
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