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If the equation x^(3)-3ax^(2)+3bx-c=0 ha...

If the equation `x^(3)-3ax^(2)+3bx-c=0` has positive and distinct roots, then

A

`a^(2)gt b`

B

`ab gt c^(2)`

C

`a^(3)gt c^(2)`

D

`a^(3)gt b^(2)gt c`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the cubic equation given by \( x^3 - 3ax^2 + 3bx - c = 0 \) and find the conditions under which it has positive and distinct roots. We will use Vieta's formulas and some inequalities to derive the necessary conditions. ### Step-by-Step Solution: 1. **Identify the Roots:** Let the roots of the cubic equation be \( \alpha, \beta, \gamma \). According to Vieta's formulas: - The sum of the roots \( \alpha + \beta + \gamma = 3a \) - The sum of the product of the roots taken two at a time \( \alpha\beta + \beta\gamma + \gamma\alpha = 3b \) - The product of the roots \( \alpha\beta\gamma = c \) 2. **Apply the AM-GM Inequality:** Since the roots are positive, we can apply the Arithmetic Mean-Geometric Mean (AM-GM) inequality: \[ \frac{\alpha + \beta + \gamma}{3} \geq \sqrt[3]{\alpha\beta\gamma} \] Substituting the values from Vieta's: \[ \frac{3a}{3} \geq \sqrt[3]{c} \implies a \geq \sqrt[3]{c} \] 3. **Use the Condition for Distinct Roots:** For the cubic equation to have distinct roots, we need to ensure that the discriminant is positive. However, we can also derive a relationship using the squares of the sums: \[ (\alpha + \beta + \gamma)^2 = \alpha^2 + \beta^2 + \gamma^2 + 2(\alpha\beta + \beta\gamma + \gamma\alpha) \] Rearranging gives: \[ \alpha^2 + \beta^2 + \gamma^2 = (\alpha + \beta + \gamma)^2 - 2(\alpha\beta + \beta\gamma + \gamma\alpha) \] Substituting the values: \[ \alpha^2 + \beta^2 + \gamma^2 = (3a)^2 - 2(3b) = 9a^2 - 6b \] 4. **Ensure Positivity:** For the roots to be distinct, we need: \[ \alpha^2 + \beta^2 + \gamma^2 - (\alpha\beta + \beta\gamma + \gamma\alpha) > 0 \] This simplifies to: \[ 9a^2 - 6b - 3b > 0 \implies 9a^2 - 9b > 0 \implies a^2 > b \] 5. **Final Conclusion:** From the analysis, we conclude that for the cubic equation \( x^3 - 3ax^2 + 3bx - c = 0 \) to have positive and distinct roots, the following condition must hold: \[ a^2 > b \]
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