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Find the intersection of the sets A={1...

Find the intersection of the sets
`A={1,2,3,4,5,6}`, `B={2,4,5}`, `C={2,6}` and show that `(AnnB)nnC=Ann(BnnC)`.

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The correct Answer is:
To solve the problem, we need to find the intersection of the sets \( A \), \( B \), and \( C \), and then show that \( (A \cap B) \cap C = A \cap (B \cap C) \). ### Step-by-Step Solution: 1. **Identify the Sets:** - \( A = \{1, 2, 3, 4, 5, 6\} \) - \( B = \{2, 4, 5\} \) - \( C = \{2, 6\} \) 2. **Find \( A \cap B \):** - The intersection \( A \cap B \) consists of elements that are in both \( A \) and \( B \). - Common elements: \( 2, 4, 5 \) - Thus, \( A \cap B = \{2, 4, 5\} \) 3. **Find \( A \cap C \):** - The intersection \( A \cap C \) consists of elements that are in both \( A \) and \( C \). - Common elements: \( 2 \) - Thus, \( A \cap C = \{2\} \) 4. **Find \( B \cap C \):** - The intersection \( B \cap C \) consists of elements that are in both \( B \) and \( C \). - Common elements: \( 2 \) - Thus, \( B \cap C = \{2\} \) 5. **Calculate \( (A \cap B) \cap C \):** - We already found \( A \cap B = \{2, 4, 5\} \). - Now we find the intersection of this set with \( C \): - \( (A \cap B) \cap C = \{2, 4, 5\} \cap \{2, 6\} \) - Common element: \( 2 \) - Thus, \( (A \cap B) \cap C = \{2\} \) 6. **Calculate \( A \cap (B \cap C) \):** - We already found \( B \cap C = \{2\} \). - Now we find the intersection of \( A \) with this set: - \( A \cap (B \cap C) = A \cap \{2\} \) - Common element: \( 2 \) - Thus, \( A \cap (B \cap C) = \{2\} \) 7. **Conclusion:** - We have found that \( (A \cap B) \cap C = \{2\} \) and \( A \cap (B \cap C) = \{2\} \). - Therefore, \( (A \cap B) \cap C = A \cap (B \cap C) \). ### Final Result: \[ (A \cap B) \cap C = A \cap (B \cap C) = \{2\} \]
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