Home
Class 12
MATHS
f(x)=x sgn (x^(2)) should be...

`f(x)=x sgn (x^(2))` should be

A

`x, x gt 0`

B

`x, x lt 0`

C

`0,x=0`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the function \( f(x) = x \cdot \text{sgn}(x^2) \). ### Step 1: Understand the Signum Function The signum function, denoted as \(\text{sgn}(x)\), is defined as: - \(\text{sgn}(x) = 1\) if \(x > 0\) - \(\text{sgn}(x) = -1\) if \(x < 0\) - \(\text{sgn}(x) = 0\) if \(x = 0\) ### Step 2: Determine the Value of \( \text{sgn}(x^2) \) Since \(x^2\) is always non-negative: - If \(x \neq 0\), \(x^2 > 0\) and thus \(\text{sgn}(x^2) = 1\). - If \(x = 0\), then \(\text{sgn}(x^2) = 0\). ### Step 3: Evaluate \( f(x) \) for Different Cases Now we can evaluate \( f(x) \) based on the value of \( x \): 1. **Case 1: \( x > 0 \)** - Here, \( \text{sgn}(x^2) = 1 \). - Therefore, \( f(x) = x \cdot 1 = x \). 2. **Case 2: \( x < 0 \)** - Here, \( \text{sgn}(x^2) = 1 \). - Therefore, \( f(x) = x \cdot 1 = x \). 3. **Case 3: \( x = 0 \)** - Here, \( \text{sgn}(x^2) = 0 \). - Therefore, \( f(x) = 0 \cdot 0 = 0 \). ### Step 4: Summarize the Results From the evaluations: - If \( x > 0 \), then \( f(x) = x \). - If \( x < 0 \), then \( f(x) = x \). - If \( x = 0 \), then \( f(x) = 0 \). ### Conclusion Thus, we can conclude: - \( f(x) = x \) for \( x > 0 \) - \( f(x) = x \) for \( x < 0 \) - \( f(x) = 0 \) for \( x = 0 \) ### Final Answer All options are correct: 1. \( f(x) = x \) if \( x > 0 \) 2. \( f(x) = x \) if \( x < 0 \) 3. \( f(x) = 0 \) if \( x = 0 \) 4. None of these (not applicable)
Promotional Banner

Topper's Solved these Questions

  • SET, RELATION & FUNCTION

    FIITJEE|Exercise Assigment problem ( OBJECTIVE )level II ( NUMERIAL BASED )|3 Videos
  • SET, RELATION & FUNCTION

    FIITJEE|Exercise COMPREHENSIONS|5 Videos
  • SET, RELATION & FUNCTION

    FIITJEE|Exercise Assigment problem ( OBJECTIVE )level I|20 Videos
  • QUADRATIC EQUATION & EXPRESSION

    FIITJEE|Exercise NUMERICAL BASED|3 Videos
  • STATISTICS

    FIITJEE|Exercise Comprehension Type|6 Videos

Similar Questions

Explore conceptually related problems

Let f(x)=sgn (sgn (sgn x)). Then lim_(x to0) f(x) is

Find the range of the following (i) f(x)="sgn"(x^(2)) " (ii) "f(x)="sgn"(x^(2)-2x+3)

If f(x)=sgn(x^(3)-x) is discontinuous at x

Draw the graph of f(x) = "sgn"(x^(3) -x) .

Let f(x)=sgn(x) and g(x)=x(1-x^(2)) The number of points at which f(g(x)) is not continuous and non-differentiable is

If f(x)=sgn(x^(5)), then which of the following is/are false (where sgn denotes signum function)

If Set A denotes the range of function to f(x)=Sgn(x^(2)-4x+4), then n(A) is

f(x)=sgn(x^(2)-ax+1) has maximum number of points of discontinuity then